Make it possible to extract video id from url
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@@ -1,5 +1,6 @@
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import argparse
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from pathlib import Path
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from pytchat.util.extract_video_id import extract_video_id
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from .arguments import Arguments
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from .. exceptions import InvalidVideoIdException, NoContents
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from .. processors.html_archiver import HTMLArchiver
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@@ -19,16 +20,19 @@ https://github.com/PetterKraabol/Twitch-Chat-Downloader
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def main():
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# Arguments
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parser = argparse.ArgumentParser(description=f'pytchat v{__version__}')
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parser.add_argument('-v', f'--{Arguments.Name.VIDEO}', type=str,
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help='Video IDs separated by commas without space.\n'
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# parser.add_argument('VideoID_or_URL', type=str, default='__NONE__',nargs='?',
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# help='Video ID, or URL that includes id.\n'
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# 'If ID starts with a hyphen (-), enclose the ID in square brackets.')
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parser.add_argument('-v', f'--{Arguments.Name.VIDEO_IDS}', type=str,
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help='Video ID (or URL that includes Video ID). You can specify multiple video IDs by separating them with commas without spaces.\n'
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'If ID starts with a hyphen (-), enclose the ID in square brackets.')
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parser.add_argument('-o', f'--{Arguments.Name.OUTPUT}', type=str,
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help='Output directory (end with "/"). default="./"', default='./')
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parser.add_argument(f'--{Arguments.Name.VERSION}', action='store_true',
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help='Settings version')
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help='Show version')
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Arguments(parser.parse_args().__dict__)
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if Arguments().print_version:
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print(f'pytchat v{__version__}')
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print(f'pytchat v{__version__} © 2019 taizan-hokuto')
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return
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# Extractor
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@@ -43,14 +47,16 @@ def main():
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f" channel: {info.get_channel_name()}\n"
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f" title: {info.get_title()}")
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path = Path(Arguments().output + video_id + '.html')
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print(f"output path: {path.resolve()}")
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print(f" output path: {path.resolve()}")
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Extractor(video_id,
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processor=HTMLArchiver(
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Arguments().output + video_id + '.html'),
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callback=_disp_progress
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).extract()
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print("\nExtraction end.\n")
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except (InvalidVideoIdException, NoContents) as e:
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except InvalidVideoIdException:
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print("Invalid Video ID or URL:", video_id)
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except (TypeError, NoContents) as e:
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print(e)
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return
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parser.print_help()
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